2 kg દળ અને 0.2 m ત્રિજ્યાનો ઘન નળાકાર 3 rad | vedclass

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Question

$\,{(K.E.)_i} = \,\,\,\frac{1}{2}\,\,I{\omega ^2} + \frac{1}{2}\,\,m{v^2}\,\,$

$ = \,\,\frac{1}{2}\,\, 	imes \,\,\frac{1}{2}\,\, 	imes \,\,2\,\,

Vedclass · Accepted Answer

$3.25$

Vedclass · Answer

$\,{(K.E.)_i} = \,\,\,\frac{1}{2}\,\,I{\omega ^2} + \frac{1}{2}\,\,m{v^2}\,\,$

$ = \,\,\frac{1}{2}\,\, 	imes \,\,\frac{1}{2}\,\, 	imes \,\,2\,\, 	imes \,\,{(0.2)^2} 	imes \,\,{(3)^2} + \frac{1}{2}\,\, 	imes \,\,0.5\,\, 	imes \,\,{(5)^2}\,\,$

$= \,\,6.43\,\,J$

${(K.E.)_f}\, = \,\,\frac{1}{2}\,\,(I\,\, + \,\,m{R^2}){\omega ^2}$

$ = \frac{1}{2}\,\,\left( {\frac{1}{2}\,\, 	imes \,\,2\,\,\, 	imes \,\,{{(0.2)}^2} + 0.5\,\,\,{{(0.2)}^2}} ight)\,\,\,{(10.3)^2}\,\, = \,\,3.18\,J$

$ \Rightarrow \,\,\,{E_{loss}}\, = \,\,K{E_i} - K{E_f}\, = \,\,6.43\, - \,\,3.18\,\, $

$= \,\,3.25\,J$

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