English
Hindi
1. Electric Charges and Fields
normal

[$\varepsilon_0$] ને શૂન્યવકાશની પરિમિટિવિટિનું પારિમાણિક સૂત્ર છે. જો $M$ = દળ, $L$ = લંબાઈ, $T$ = સમય અને $A$ = વિદ્યુતપ્રવાહ તો......

A

[$\varepsilon_0$] = [$M^{-1} L^{-3} T^2A$]

B

[$\varepsilon_0$] = [$M^{-1} L^{-3} T^4 A^2$]

C

[$\varepsilon_0$] = [$M^{-1} L^2 T^{-1} A^{-2}$]

D

[$\varepsilon_0$] = [$M^{-1} L^2 T^{-1} A$]

Solution

$F  =  \frac{1}{{4\pi { \in _0}}}\,\,\frac{{{q_1}{q_2}}}{{{r^2}}}$

$\left[ {ML{T^{ – 2}}} \right]\,\, = \,\,\left[ {\frac{1}{{{ \in _0}}}} \right]\,\,\frac{{{A^2}{T^2}}}{{{L^2}}}\,\,\, $

$\Rightarrow \,\,\left[ {{\varepsilon _0}} \right]\,\, = \,\,\left[ {{M^{ – 1}}{L^{ – 3}}{T^4}{A^2}} \right]$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.