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8. Sequences and Series
medium
સમગુણોત્તર શ્રેણી $8 + 12 + 18 + 27 + …..$ ના $9$ મું પદ મેળવો.
A
$6561/32$
B
$6023/33$
C
$5897/30$
D
$4578/34$
Solution
$\because \,\,{\text{a}} = {\text{8, r}} = \frac{{\text{3}}}{{\text{2}}}\,\,$
$\therefore \,\,{{\text{T}}_{\text{9}}} = {\text{8}}\,{\text{.}}\,\,{\left( {\frac{{\text{3}}}{{\text{2}}}} \right)^{\text{8}}} = \frac{{{\text{6561}}}}{{{\text{32}}}}$
Standard 11
Mathematics
