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14.Probability
medium
ઘટના ${\text{A, B}}$ છે $P(A \cup B)\,\, = \,\,\frac{3}{4},\,P(A \cap B)\,\, = \,\,\frac{1}{4},\,P(A')\,\, = \,\,\frac{2}{3}$ તો ${\text{P (A' }} \cap {\text{ B)}} = ......$
A
$5/12$
B
$3/8$
C
$5/8$
D
$1/4$
Solution
$P (A) = 1- P(A') = 1 – 2/3 = 1/3$
હવે$,P (A \cup B)= P (A) + P (B) – P (A \cap C)$
$\begin{gathered}
\frac{3}{4} = \frac{1}{3}\, + P\,(B)\, – \frac{1}{4}\,\,\,\therefore \,\,\,\,P(B)\, = \frac{3}{4}\, + \frac{1}{4}\, – \,\frac{1}{3}\, = \frac{2}{3} \hfill \\
P(A' \cap B)\, = \,P\,(B)\, – P\,(A \cap B)\, = \,\frac{2}{3} – \frac{1}{4} = \frac{5}{{12}} \hfill \\
\end{gathered} $
Standard 11
Mathematics