English
Hindi
14.Probability
medium

જો $\,P(A\, \cup \,\,B)\,\, = \,\,\frac{2}{3}\,,\,\,P(A\,\, \cap \,\,B)\,\, = \,\,\frac{1}{6}\,\,$ અને $\,\,P(A)\,\, = \,\,\frac{1}{3}$  હોય 

A

$A$ અને $B$ નિરપેક્ષ ઘટનાઓ છે

B

$A$ અને $B$ અલગ ઘટનાઓ છે

C

$A$ અને $B$ સાપેક્ષ ઘટનાઓ છે

D

ઉપર આપેલ એક પણ નહિં

Solution

$P(A \cup  B) = P(A) + P(B) – P(AB)$

$ \Rightarrow \,\frac{2}{3}\,\, = \,\,\frac{1}{3}\,\, + \,\,P(B)\,\, – \,\,\frac{1}{6}\,\,\,\,\, \Rightarrow \,\,\frac{2}{3}\,\, = \,\,\frac{1}{6}\,\, + \,\,P(B)\,\,\,\,\,\, \Rightarrow \,\,P(B)\,\, = \,\,\frac{1}{2}$

હવે, $P(AB) = P(A) P(B) … A$  અને $ B$  નિરપેક્ષ ઘટનાઓ છે.

Standard 11
Mathematics

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