English
Hindi
13.Statistics
hard

નીચે આપેલ આવૃત્તિ વિતરણનું વિચરણ શોધો.

$class$

$0 - 2$

$2 - 4$

$4 - 6$

$6 - 8$

 $8 - 10$

$10 - 12$

$f_i$

   $2$

   $7$

  $12$

  $19$

    $9$

    $ 1$

A

$1.5$

B

$2$

C

$3.5$

D

$4.97$

Solution

ધારો કે $= 7, h = 2$

$class$

 $x_i$

    $f_i$

$u_i = (x_i – a)/h$

     $f_iu_i$

    ${f_i}u_i^2$

$0 – 2$

 $1$

    $2$

      $-3$

     $-6$

     $18$

$2 – 4$

 $3$

    $7$

      $-2$

     $-14$

     $28$

$4 – 6$

 $5$

   $12$

      $-1$

    $-12$

     $12$

$6 – 84$

 $7$

   $19$

      $0$

      $0$

      $0$

$8 – 10$

 $9$

   $9$

      $1$

     $9$

      $9$

$10 – 12$

$11$

   $1$

      $2$

      $2$

      $4$

   

$N = 50$

 

$\sum f-iu_­I = -21$

$\sum f_iu_i^2 = 71$

 $\therefore \,{\sigma ^2}\, =\,{h^2}\,\left[ {\frac{{\Sigma {f_i}{u_i}^2}}{N}\, – \,{{\left( {\frac{{\Sigma {f_i}{u_i}}}{N}} \right)}^2}} \right]$

$ = 4\,\left[ {\frac{{71}}{{50}}\, – \,{{\left( {\frac{{ – 21}}{{50}}} \right)}^2}} \right]\, = \,4[1.42 – 0.1764] = 4.97$

Standard 11
Mathematics

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