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1.Units, Dimensions and Measurement
normal
એક ઘનની બાજુની લંબાઈ $ 1.2 × 10^{-2} $છે તેનું કદ ગણો.
A
$1.7 × 10^{-6}m^{3}$
B
$1.73 × 10^{-6}m^{3}$
C
$1.72 × 10^{-6} m^{3}$
D
$1.728 ×10^{-6} m^{3}$
Solution
Length of the cube, $L =1.2 \times 10^{-2} m$
$\therefore$ Volume of the cube, $V = L ^3=\left(1.2 \times 10^{-2}\right) \times\left(1.2 \times 10^{-2}\right) \times\left(1.2 \times 10^{-2}\right) m ^3$ $\Rightarrow V =1.728 \times 10^{-6} m ^3$
But as the length contains only $2$ significant digits, thus volume must also contain $2$ significant digits.
Hence, volume of the cube is $1.7 \times 10^{-6}\,m ^3$
Standard 11
Physics
