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Hindi
3-2.Motion in Plane
medium

દડાને મહત્તમ અંતર $80 \,m$ સુધી ફેંકી શકાતો હોય,તો મહત્તમ કેટલા.........$m$ ઊંચાઇ સુધી ફેંકી શકાય?

A

$10$

B

$15$

C

$30 $

D

$40$

Solution

${R_{\max }} = \frac{{{u^2}}}{g} = 80\,m$ [ $\theta = 45^\circ $]

${H_{\max }} = \frac{{{u^2}{{\sin }^2}{{90}^o}}}{{2g}}$$ = \frac{{{u^2}}}{{2g}}$

$\therefore {H_{\max }} = \frac{1}{2}\left( {\frac{{{u^2}}}{g}} \right)$

$\therefore {H_{\max }} = 40 \,m$

Standard 11
Physics

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