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3-2.Motion in Plane
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પદાર્થનું દળ, ઝડપ અને ત્રિજયામાં $50\%$ નો વધારો થાય, તો કેન્દ્રગામી બળમાં ...... $\%$ વધારો થશે?
A$225$
B$125$
C$150$
D$100$
Solution
$F = \frac{{m\,{v^2}}}{r}$
$F' = \frac{{\left( {m + \frac{m}{2}} \right)\,\,{{\left( {v + \frac{v}{2}} \right)}^2}}}{{\left( {r + \frac{r}{2}} \right)}}$ $= \frac{9}{4}\frac{{m\,{v^2}}}{r}$
$\therefore F' = \frac{9}{4}F$
$\frac{{\Delta F}}{F} \times 100\,\, = \frac{{F'\, – F}}{F} \times 100\% \, = \frac{{500}}{4}\% = 125 \,\%$
$F' = \frac{{\left( {m + \frac{m}{2}} \right)\,\,{{\left( {v + \frac{v}{2}} \right)}^2}}}{{\left( {r + \frac{r}{2}} \right)}}$ $= \frac{9}{4}\frac{{m\,{v^2}}}{r}$
$\therefore F' = \frac{9}{4}F$
$\frac{{\Delta F}}{F} \times 100\,\, = \frac{{F'\, – F}}{F} \times 100\% \, = \frac{{500}}{4}\% = 125 \,\%$
Standard 11
Physics
