English
Hindi
9-1.Fluid Mechanics
normal

આકૃતિમાં પ્રવાહીનો વેગ $v=$ ______ $\mathrm{m/s}$

A

$3$

B

$1.5$

C

$1$

D

$2.25$

Solution

$\therefore \;M = {m_1} + {m_2}$

==> $A{v_1} = A{v_2} + 1.5A\,.\,v$

==> $A \times 3 = A \times 1.5 + 1.5A\,.\,v$

==> $v = 1\;m/s$

Standard 11
Physics

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