$E,\,m,\,l$ and $G$ denote energy, mass, angular momentum and gravitational constant respectively, then the dimension of $\frac{{E{l^2}}}{{{m^5}{G^2}}}$ are
$E,\,m,\,l$ and $G$ denote energy, mass, angular momentum and gravitational constant respectively, then the dimension of $\frac{{E{l^2}}}{{{m^5}{G^2}}}$ are
- [AIIMS 1985]
- A
Angle
- B
Length
- C
Mass
- D
Time
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Identify the pair of physical quantities that have same dimensions
Identify the pair of physical quantities that have same dimensions
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The dimension of $\frac{\mathrm{B}^{2}}{2 \mu_{0}}$, where $\mathrm{B}$ is magnetic field and $\mu_{0}$ is the magnetic permeability of vacuum, is
The dimension of $\frac{\mathrm{B}^{2}}{2 \mu_{0}}$, where $\mathrm{B}$ is magnetic field and $\mu_{0}$ is the magnetic permeability of vacuum, is
- [JEE MAIN 2020]
If orbital velocity of planet is given by $v = {G^a}{M^b}{R^c}$, then
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If $\varepsilon_0$ is permittivity of free space, $e$ is charge of proton, $G$ is universal gravitational constant and $m_p$ is mass of a proton then the dimensional formula for $\frac{e^2}{4 \pi \varepsilon_0 G m_p{ }^2}$ is
If $\varepsilon_0$ is permittivity of free space, $e$ is charge of proton, $G$ is universal gravitational constant and $m_p$ is mass of a proton then the dimensional formula for $\frac{e^2}{4 \pi \varepsilon_0 G m_p{ }^2}$ is
In the expression $P = El^2m^{-5}G^{-2}$, $E$, $l$, $m$ and $G$ denote energy, mass, angular momentum and gravitational constant respectively. Show that $P$ is a dimensionless quantity.
In the expression $P = El^2m^{-5}G^{-2}$, $E$, $l$, $m$ and $G$ denote energy, mass, angular momentum and gravitational constant respectively. Show that $P$ is a dimensionless quantity.