$\frac{{\tan \,\,\left( {x\,\, - \,\,{\textstyle{\pi \over 2}}} \right)\,\,.\,\,\cos \,\,\left( {{\textstyle{{3\pi } \over 2}}\,\, + \,\,x} \right)\,\, - \,\,{{\sin }^3}\,\left( {{\textstyle{{7\pi } \over 2}}\,\, - \,\,x} \right)}}{{\cos \,\,\left( {x\,\, - \,\,{\textstyle{\pi \over 2}}} \right)\,\,.\,\,\tan \,\,\left( {{\textstyle{{3\pi } \over 2}}\,\, + \,\,x} \right)}}$ =
$sin \,x\, cos\, x$
$- sin^2\, x$
$- sin\, x\, cos\, x$
$sin^2x$
$4 \,\,sin5^o \,\,sin55^o \,\,sin65^o$ =
ત્રિકોણ $ABC$ માટે ,$\sin A + \sin B + \sin C = . . . .$
$\frac{{\sqrt {1 + \sin x} + \sqrt {1 - \sin x} }}{{\sqrt {1 + \sin x} - \sqrt {1 - \sin x} }} = $ (કે જ્યાં $x$ એ બીજા ચરણમાં છે.)
જો $cosec^2\theta $ = $\frac{4xy}{(x +y)^2}$ હોય તો
$\tan 7\frac{1}{2}^\circ =...$