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જો $A + B + C = {180^o},$ તો $\cot \frac{A}{2} + \cot \frac{B}{2} + \cot \frac{C}{2} = . . .$
$2\cot \frac{A}{2}\cot \frac{B}{2}\cot \frac{C}{2}$
$4\cot \frac{A}{2}\cot \frac{B}{2}\cot \frac{C}{2}$
$\cot \frac{A}{2}\cot \frac{B}{2}\cot \frac{C}{2}$
$8\,\cot \frac{A}{2}\cot \frac{B}{2}\cot \frac{C}{2}$
Solution
(c) $A + B + C = {180^o}$,
$\therefore \,\frac{A}{2} + \frac{B}{2} = {90^o} – \frac{C}{2}$
$\therefore \cot \left( {\frac{A}{2} + \frac{B}{2}} \right) = \cot \left( {{{90}^o} – \frac{C}{2}} \right)$
or $\frac{{\cot \frac{A}{2}\,.\,\cot \frac{B}{2}\, – 1}}{{\cot \frac{B}{2}\, + \,\cot \frac{A}{2}}} = \tan \frac{C}{2} = \frac{1}{{\cot \frac{C}{2}}}$
or $\left( {\cot \frac{A}{2}\cot \frac{B}{2} – 1} \right)\cot \frac{C}{2} = \cot \frac{B}{2} + \cot \frac{A}{2}$
$\cot \frac{A}{2}\,.\,\cot \frac{B}{2}\,.\,\cot \frac{C}{2} = \cot \frac{C}{2} + \cot \frac{B}{2}$ $ + \cot \frac{A}{2}.$