frac{{sqrt 2 - sin alpha - cos alpha }}{{sin | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) $\frac{{\sqrt 2 - \sin \alpha - \cos \alpha }}{{\sin \alpha - \cos \alpha }}$

$= \frac{{\sqrt 2 - \sqrt 2 \left\{ {\frac{1}{{\sqrt 2 }}\sin \al

Vedclass · Accepted Answer

$	an \left( {\frac{\alpha }{2} - \frac{\pi }{8}} ight)$

Vedclass · Answer

(c) $\frac{{\sqrt 2 - \sin \alpha - \cos \alpha }}{{\sin \alpha - \cos \alpha }}$

$= \frac{{\sqrt 2 - \sqrt 2 \left\{ {\frac{1}{{\sqrt 2 }}\sin \alpha + \frac{1}{{\sqrt 2 }}\cos \alpha } ight\}}}{{\sqrt 2 \left\{ {\frac{1}{{\sqrt 2 }}\sin \alpha - \frac{1}{{\sqrt 2 }}\cos \alpha } ight\}}}$

$=\frac{{\sqrt 2 - \sqrt 2 \cos \left( {\alpha - \frac{\pi }{4}} ight)}}{{\sqrt 2 \sin \left( {\alpha - \frac{\pi }{4}} ight)}}$

$= \frac{{\sqrt 2 \left\{ {\,1 - \cos 	heta } ight\}}}{{\sqrt 2 \sin 	heta }},$   where $	heta = \alpha - \frac{\pi }{4}$

$= \frac{{2{{\sin }^2}(	heta /2)}}{{2\sin (	heta /2)\cos (	heta /2)}} = 	an \frac{	heta }{2}$ 

$ = 	an \left( {\frac{\alpha }{2} - \frac{\pi }{8}} ight)$.

$\frac{{\sqrt 2 - \sin \alpha - \cos \alpha }}{{\sin \alpha - \cos \alpha }} = $

Similar Questions

જો $\frac{x}{{\cos \theta }} = \frac{y}{{\cos \left( {\theta - \frac{{2\pi }}{3}} \right)}} = \frac{z}{{\cos \left( {\theta + \frac{{2\pi }}{3}} \right)}},$ તો $x + y + z = $

જો $\sin \theta = \frac{1}{2}\left( {\sqrt {\frac{x}{y}\,} + \,\sqrt {\frac{y}{x}} } \right)\,,\,\left( {x,y \in R\, - \{ 0\} } \right)$ થાય તો

$\frac{{\sin 3\theta - \cos 3\theta }}{{\sin \theta + \cos \theta }} + 1 = $

$\sqrt 2 + \sqrt 3 + \sqrt 4 + \sqrt 6 = . . ..$

સાબિત કરો કે : $\cos ^{2} 2 x-\cos ^{2} 6 x=\sin 4 x \sin 8 x$