4 ,,sin5^o ,,sin55^o ,,sin65^o = | vedclass

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Question

$2[2sin\,5^o \,sin\,55^o] \,sin\,65^o$

$\Rightarrow$ $2[cos\,50^o - cos\,60^o]sin\,65^o$

$\Rightarrow$ $2cos\,50^o \,sin\,65^o - sin\,65^o$

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Vedclass · Accepted Answer

$\frac{{\sqrt 3  - 1}}{{2\sqrt 2 }}$

Vedclass · Answer

$2[2sin\,5^o \,sin\,55^o] \,sin\,65^o$

$\Rightarrow$ $2[cos\,50^o - cos\,60^o]sin\,65^o$

$\Rightarrow$ $2cos\,50^o \,sin\,65^o - sin\,65^o$

$\Rightarrow$ $sin(115^o) + sin\,15^o - sin\,65^o = \frac{{\sqrt 3  - 1}}{{2\sqrt 2 }}$

$4 \,\,sin5^o \,\,sin55^o \,\,sin65^o$ =

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