4 ,,sin5^o ,,sin55^o ,,sin65^o = | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$2[2sin\,5^o \,sin\,55^o] \,sin\,65^o$

$\Rightarrow$ $2[cos\,50^o - cos\,60^o]sin\,65^o$

$\Rightarrow$ $2cos\,50^o \,sin\,65^o - sin\,65^o$

$

Vedclass · Accepted Answer

$\frac{{\sqrt 3  - 1}}{{2\sqrt 2 }}$

Vedclass · Answer

$2[2sin\,5^o \,sin\,55^o] \,sin\,65^o$

$\Rightarrow$ $2[cos\,50^o - cos\,60^o]sin\,65^o$

$\Rightarrow$ $2cos\,50^o \,sin\,65^o - sin\,65^o$

$\Rightarrow$ $sin(115^o) + sin\,15^o - sin\,65^o = \frac{{\sqrt 3  - 1}}{{2\sqrt 2 }}$

$4 \,\,sin5^o \,\,sin55^o \,\,sin65^o$ =

Similar Questions

જો $\tan \alpha = \frac{1}{7}$ અને $\sin \beta = \frac{1}{{\sqrt {10} }}\left( {0 < \alpha ,\,\beta < \frac{\pi }{2}} \right)$, તો $2\beta = . . . .$

જો $\tan x + \tan \left( {\frac{\pi }{3} + x} \right) + \tan \left( {\frac{{2\pi }}{3} + x} \right) = 3,$ તો

$\cot {70^o} + 4\cos {70^o} = . . .$

$\tan 5x\tan 3x\tan 2x = $

$1 + \cos \,{56^o} + \cos \,{58^o} - \cos {66^o} = $