$A$ particle having charge $q$ enters a region of uniform magnetic field $\vec B$ (directed inwards) and is deflected a distance $x$ after travelling a distance $y$. The magnitude of the momentum of the particle is:
$\frac{{qBy}}{2}$
$\frac{{qBy}}{x}$
$\frac{{qB}}{2}\left( {\frac{{{y^2}}}{x} + x} \right)$
$\frac{{qB{y^2}}}{{2x}}$
A charged particle moving in a magnetic field experiences a resultant force
Which of the following particle will describe the smallest circle when projected with the same velocity perpendicular to the magnetic field ?
An $\alpha -$ particle of $1\,MeV$ energy moves on circular path in uniform magnetic field. Then kinetic energy of proton in same magnetic field for circular path of double radius is......$MeV$
A particle with charge $+Q$ and mass m enters a magnetic field of magnitude $B,$ existing only to the right of the boundary $YZ$. The direction of the motion of the $m$ particle is perpendicular to the direction of $B.$ Let $T = 2\pi\frac{m}{{QB}}$ . The time spent by the particle in the field will be
Which particles will have minimum frequency of revolution when projected with the same velocity perpendicular to a magnetic field