A particle of mass 2, kg located at the posit | vedclass

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Question

The angular momentum about origin

$\overrightarrow{\mathrm{L}}=\overrightarrow{\mathrm{r}} 	imes \mathrm{m} \overrightarrow{\mathrm{v}}$

$\over

Vedclass · Accepted Answer

$-8$

Vedclass · Answer

The angular momentum about origin

$\overrightarrow{\mathrm{L}}=\overrightarrow{\mathrm{r}} 	imes \mathrm{m} \overrightarrow{\mathrm{v}}$

$\overrightarrow{\mathrm{L}}=(\hat{i}+\hat{j}) 	imes 4(\hat{i}-\hat{j}+\hat{k})$

$\overrightarrow{\mathrm{L}}=4(-\hat{\mathrm{k}}-\hat{\mathrm{j}}-\hat{\mathrm{k}}+\hat{\mathrm{i}})$

$\overrightarrow{\mathrm{L}}=4 \hat{\mathrm{i}}-4 \hat{\mathrm{j}}-8 \hat{\mathrm{k}}$

$	herefore \mathrm{L}_{\mathrm{z}}=-8 \mathrm{kg} \mathrm{m}^{2} / \mathrm{s}$

$A$ particle of mass $2\, kg$ located at the position $(\hat i + \hat j)$ $m$ has a velocity $2( + \hat i - \hat j + \hat k)m/s$. Its angular momentum about $z$ -axis in $kg-m^2/s$ is

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