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Mathematical Reasoning
normal
$\sim (p \vee q) \vee (~ p \wedge q)$ is logically equivalent to
A
$\sim p$
B
$p$
C
$q$
D
$\sim q$
Solution
$\sim (p \vee q) \vee (\sim p \wedge q))$
$\equiv (\sim p \wedge \sim q) \vee (\sim p \wedge q$
$\equiv \sim p \vee (\sim q \vee q) \equiv \sim p$
Standard 11
Mathematics