∼ (p vee q) vee (~ p wedge q) is logically equivalent to

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Mathematical Reasoning

normal

$\sim (p \vee q) \vee (~ p \wedge q)$ is logically equivalent to

A

$\sim p$

B

$p$

C

$q$

D

$\sim q$

Solution

$\sim (p \vee q) \vee (\sim p \wedge q))$
$\equiv (\sim p \wedge \sim q) \vee (\sim p \wedge q$
$\equiv \sim p \vee (\sim q \vee q) \equiv \sim p$

Standard 11

Mathematics

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