A = {1,2,3,4......100}, B = {51,52,53,...,180 | vedclass

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Question

$n(A \cap B)=50$

so total number of common elements in $(\mathrm{A} 	imes \mathrm{B})$

and $\mathrm{B} 	imes \mathrm{A} \Rightarrow \mathrm{n}

Vedclass · Accepted Answer

$2500$

Vedclass · Answer

$n(A \cap B)=50$

so total number of common elements in $(\mathrm{A} 	imes \mathrm{B})$

and $\mathrm{B} 	imes \mathrm{A} \Rightarrow \mathrm{n}((\mathrm{A} 	imes \mathrm{B}) \cap(\mathrm{B} 	imes \mathrm{A}))=2500$

$A = \{1,2,3,4......100\}, B = \{51,52,53,...,180\}$, then number of elements in $(A \times B) \cap (B \times A)$ is

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