A = {1,2,3,4......100}, B = {51,52,53,...,180} , then number of elements in (A × B) cap

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2.Relations and Functions

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$A = \{1,2,3,4......100\}, B = \{51,52,53,...,180\}$, then number of elements in $(A \times B) \cap (B \times A)$ is

A

$1800$

B

$1600$

C

$2500$

D

$1500$

Solution

$n(A \cap B)=50$

so total number of common elements in $(\mathrm{A} \times \mathrm{B})$

and $\mathrm{B} \times \mathrm{A} \Rightarrow \mathrm{n}((\mathrm{A} \times \mathrm{B}) \cap(\mathrm{B} \times \mathrm{A}))=2500$

Standard 11

Mathematics

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