7.Alternating Current
medium

A $40\, \mu F$ capacitor is connected to a $200\, V , 50 \,Hz$ ac supply. The rms value of the current in the circult is, nearly $.......A$

A

$25.1$

B

$1.7$

C

$2.05$

D

$2.5$

(NEET-2020)

Solution

$I=\frac{V}{X_{C}}=\frac{V}{1 / C \omega}=V C \omega$

$=200 \times 40 \times 10^{-6} \times 2 \pi \times 50$

$=2.5 A$

Standard 12
Physics

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