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7.Alternating Current
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A $40\, \mu F$ capacitor is connected to a $200\, V , 50 \,Hz$ ac supply. The rms value of the current in the circult is, nearly $.......A$
A
$25.1$
B
$1.7$
C
$2.05$
D
$2.5$
(NEET-2020)
Solution
$I=\frac{V}{X_{C}}=\frac{V}{1 / C \omega}=V C \omega$
$=200 \times 40 \times 10^{-6} \times 2 \pi \times 50$
$=2.5 A$
Standard 12
Physics