8.Mechanical Properties of Solids
easy

A $100\,m$ long wire having cross-sectional area $6.25 \times 10^{-4}\,m ^2$ and Young's modulus is $10^{10}\,Nm ^{-2}$ is subjected to a load of $250\,N$, then the elongation in the wire will be :

A

$6.25 \times 10^{-3}\,m$

B

$4 \times 10^{-4}\,m$

C

$6.25 \times 10^{-6}\,m$

D

$4 \times 10^{-3}\,m$

(JEE MAIN-2023)

Solution

Elongation in wire $\delta=\frac{ F \ell}{ AY }$

$\delta=\frac{250 \times 100}{6.25 \times 10^{-4} \times 10^{10}}$

$\delta=4 \times 10^{-3}\,m$

Standard 11
Physics

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