A 2, kg stone at end of a string 1 ,m long is whirled in a vertical circle at a constant speed. spee

English

Gujarati

Hindi

5.Work, Energy, Power and Collision

medium

A $2\, kg$ stone at the end of a string $1 \,m$ long is whirled in a vertical circle at a constant speed. The speed of the stone is $4 \,m/sec$. The tension in the string will be $52\, N$, when the stone is

A

At the top of the circle

B

At the bottom of the circle

C

Halfway down

D

None of the above

(AIIMS-1982)

Solution

(b) $mg = 20N$ and $\frac{{m{v^2}}}{r} = \frac{{2 \times {{(4)}^2}}}{1} = 32N$

It is clear that $52 \,N$ tension will be at the bottom of the circle. Because we know that

${T_{{\rm{Bottom}}}} = mg + \frac{{m{v^2}}}{r}$

Standard 11

Physics

Share

Similar Questions

A body of mass $m$ hangs at one end of a string of length $l$, the other end of which is fixed. It is given a horizontal velocity so that the string would just reach where it makes an angle of $60^o$ with the vertical. The tension in the string at mean position is

medium

A point mass '$m$" is moved in a vertical circle of radius 'r" with the help of a string. The velocity of the mass is $\sqrt{7 gr }$ at the lowest point. The tension in the string at the lowest point is ………. $mg$

medium

(NEET-2020)

$A$ small cube with mass $M$ starts at rest at point $1$ at a height $4R$, where $R$ is the radius of the circular part of the track. The cube slides down the frictionless track and around the loop. The force that the track exerts on the cube at point $2$ is nearly ……… times the cube's weight $mg$.

hard

A cane filled with water is revolved in a vertical circle of radius $4 $ meter and the water just does not fall down. The time period of revolution will be …….. $\sec$

medium

The bob of a simple pendulum is of mass $10\, gm$. It is suspended with a thread of $1\, m$. If we hold the bob so as to stretch the string horizontally and release it. What will be the tension at the lowest position ……… $N$

medium