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14.Probability
easy
Three integers are chosen at random from the first $20$ integers. The probability that their product is even, is
A
$\frac{2}{{19}}$
B
$\frac{3}{{29}}$
C
$\frac{{17}}{{19}}$
D
$\frac{4}{{19}}$
Solution
(c) The total number of ways in which $3$ integers can be chosen from first $20$ integers is $^{20}{C_3}.$
The product of three integers will be even if at least one of them is even.
$\therefore $ Required probability $ = 1 -$ Probability that none is even
$ = 1 – \frac{{^{10}{C_3}}}{{^{20}{C_3}}} = 1 – \frac{2}{{19}} = \frac{{17}}{{19}}.$
Standard 11
Mathematics