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5.Work, Energy, Power and Collision
medium
A ball of mass $0.1$ kg is suspended by a string. It is displaced through an angle of ${60^o}$ and left. When the ball passes through the mean position, the tension in the string is ........ $N$
A$19.6$
B$1.96 $
C$9.8 $
D$0$
Solution
(b) $T = mg + \frac{{m{v^2}}}{l}$ = $mg + \frac{m}{l}\left[ {2gl(1 – \cos \theta )} \right]$
=$mg + 2mg(1 – \cos 60^\circ )$=$2mg$ $=2× 0.1 × 9.8=1.96N$
=$mg + 2mg(1 – \cos 60^\circ )$=$2mg$ $=2× 0.1 × 9.8=1.96N$
Standard 11
Physics
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