A stone is projected in air. Its time of flight is 3,s and range is 150,m Maximum height reached by

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3-2.Motion in Plane

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A stone is projected in air. Its time of flight is $3\,s$ and range is $150\,m$ Maximum height reached by the stone is $......\,m$ $\left(g=10\,ms ^{-2}\right)$

A

$37.5$

B

$22.5$

C

$90$

D

$11.25$

Solution

(d)

$T=\frac{2 u_y}{g}=3$

$\therefore \quad u_y=15\,m / s$

Now,

$H=\frac{u_y^2}{2 g}=\frac{(15)^2}{20}=11.25\,m$

Standard 11

Physics

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(JEE MAIN-2021)