A bar magnet of length 6,cm has a magnetic mo | vedclass

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Question

Along the equatorial line, magnetic field strength

$B = \frac{{{\mu _0}}}{{4\pi }}\frac{M}{{{{({r^2} + {l^2})}^{3/2}}}}$

Given: $M=4\, \mathrm{J

Vedclass · Accepted Answer

$5	imes 10^{-8}\,tesla$

Vedclass · Answer

Along the equatorial line, magnetic field strength

$B = \frac{{{\mu _0}}}{{4\pi }}\frac{M}{{{{({r^2} + {l^2})}^{3/2}}}}$

Given: $M=4\, \mathrm{J} T^{-1}$

$r=200 \,\mathrm{cm}=2 \,\mathrm{m}$

$\ell=\frac{6 \,\mathrm{cm}}{2}=3\, \mathrm{cm}=3 	imes 10^{-2}\, \mathrm{m}$

$	herefore B=\frac{4 \pi 	imes 10^{-7}}{4 \pi} 	imes \frac{4}{\left[2^{2}+\left(3 	imes 10^{-2}ight)^{2}ight]^{3 / 2}}$

Solving we get, $B=5 	imes 10^{-8}$ $tesla$

A bar magnet of length $6\,cm$ has a magnetic moment of $4\,J\,T^{-1}$. Find the strength of magnetic field at a distance of $200\,cm$ from the centre of the magnet along its equatorial line.

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