A block of mass m , is kept on a wedge of mass M , as shown in figure such that mass m remains stati

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4-1.Newton's Laws of Motion

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A block of mass $m$, is kept on a wedge of mass $M$, as shown in figure such that mass $m$ remains stationary w.r.t. wedge. The magnitude of force $P$ is

A

$g \tan \beta$

B

$m g \tan \beta$

C

$(m+M) g \tan \beta$

D

$m g \cot \beta$

Solution

(c)

If acceleration of the system is a then $P=(M+m) a$ from the reference frame of wedge

Component of ma along the inclined will be $m a \cos \beta$ for the block to be in equilibrium w.r.t. wedge

$m a \cos \beta=m g \sin \beta$

$a=g \tan \beta$

hence $P=(M+m) g \tan \beta$

Standard 11

Physics

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