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9-1.Fluid Mechanics
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A body floats in a liquid contained in a beaker. The whole system as shown falls freely under gravity. The upthrust on the body due to the liquid is

A
Zero
B
Equal to the weight of the liquid displaced
C
Equal to the weight of the body in air
D
Equal to the weight of the immersed position of the body
(IIT-1982)
Solution
(a)Upthrust $ = V{\rho _{{\rm{liquid}}}}(g – a)$
where, $a = $ downward acceleration,
$V = $ volume of liquid displaced
But for free fall $ a = g $ $\therefore $ $Upthrust = 0$
Standard 11
Physics
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