A body is at rest under action of three forces, two of which are {vec F₁} = 4hat{i},,{vec F₂} =

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3-1.Vectors

easy

A body is at rest under the action of three forces, two of which are ${\vec F_1} = 4\hat i,\,{\vec F_2} = 6\hat j,$ the third force is

A

$4\hat i + 6\hat j$

B

$4\hat i - 6\hat j$

C

$ - 4\hat i + 6\hat j$

D

$ - 4\hat i - 6\hat j$

Solution

(d) ${F_1} + {F_2} + {F_3} = 0$ $⇒$ $4\hat i + 6\hat j + {F_3} = 0$

$\therefore {\vec F_3} = – 4\hat i – 6\hat j$

Standard 11

Physics

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