A body is at rest under the action of three forces, two of which are ${\vec F_1} = 4\hat i,\,{\vec F_2} = 6\hat j,$ the third force is
$4\hat i + 6\hat j$
$4\hat i - 6\hat j$
$ - 4\hat i + 6\hat j$
$ - 4\hat i - 6\hat j$
The three vectors $\overrightarrow A = 3\hat i - 2\hat j + \hat k,\,\,\overrightarrow B = \hat i - 3\hat j + 5\hat k$ and $\overrightarrow C = 2\hat i + \hat j - 4\hat k$ form
The vectors $\overrightarrow A $ and $\overrightarrow B$ lie in a plane. Another vector $\overrightarrow C $ lies outside this plane. The resultant $\overrightarrow A + \overrightarrow B + \overrightarrow C$ of these three vectors
Two vectors $\overrightarrow{{X}}$ and $\overrightarrow{{Y}}$ have equal magnitude. The magnitude of $(\overrightarrow{{X}}-\overrightarrow{{Y}})$ is ${n}$ times the magnitude of $(\overrightarrow{{X}}+\overrightarrow{{Y}})$. The angle between $\overrightarrow{{X}}$ and $\overrightarrow{{Y}}$ is -