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3-1.Vectors
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If $a$ and $b$ are two units vectors inclined at an angle of $60^{\circ}$ to each other, then
A$| a + b | > 1$
B$|a+b| < 1$
C$| a - b | > 1$
D$|a-b| < 1$
Solution
(a)
$\vec{A}+\vec{B} =\sqrt{1+1+2 \times 1 \times 1 \cos 60}$
$=\sqrt{3} > 1$
$\vec{A}+\vec{B} =\sqrt{1+1+2 \times 1 \times 1 \cos 60}$
$=\sqrt{3} > 1$
Standard 11
Physics
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