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6.System of Particles and Rotational Motion
medium
A body is rolling without slipping on a horizontal plane. If the rotational energy of the body is $40\%$ of the total kinetic energy, then the body might be
A
Cylinder
B
Hollow sphere
C
Solid cylinder
D
ring
Solution
$\frac{\frac{1}{2} I \omega^{2}}{\frac{1}{2} m v^{2}}=\frac{40}{60}$
$v=R \omega$
hence $I=\frac{2}{3} m R^{2}$
$Hollow \,sphere$
Standard 11
Physics