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7. MOTION
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एक पिंड, वेग $'u'$ से ऊर्ध्वाधर ऊपर फेंका जाता है। इसके ऊपर उठने की अधिकतम ऊँचाई $'h'$ होगी
A
$u/g$
B
$u^2/2g$
C
$u^2/g$
D
$u/2g$
Solution
The body that is thrown vertically upward with velocity $u$ will have final velocity $v =0$ at the greatest height $h$.
Substituting the given values in the third equation of motion, $v^{2}=u^{2}+2$ as we have $0=u^{2}-2 g h$. (taking $g$ in the upward direction)
$h=\frac{u^{2}}{2 g}$
Standard 9
Science
