A body of mass 2, kg slides down a curved track which is quadrant of a circle of radius 1 meter as s

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5.Work, Energy, Power and Collision

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A body of mass $2\, kg$ slides down a curved track which is quadrant of a circle of radius $1$ $meter$ as shown in figure. All the surfaces are frictionless. If the body starts from rest, its speed at the bottom of the track is ............. $\mathrm{m}/ \mathrm{s}$

A

$4.43$

B

$2$

C

$0.5$

D

$19.6$

Solution

By conservation of energy

$\mathrm{v}^{2}=2 \mathrm{gh} \Rightarrow \mathrm{v}=\sqrt{2 \times 9.8}=4.43 \mathrm{m} / \mathrm{s}$

Standard 11

Physics

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