A truck and a car are moving with equal velocity. On applying brakes both will stop after certain di

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5.Work, Energy, Power and Collision

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A truck and a car are moving with equal velocity. On applying the brakes both will stop after certain distance, then

ATruck will cover less distance before rest

BCar will cover less distance before rest

CBoth will cover equal distance

DNone

Solution

(b) Stopping distance $ = \frac{{{\rm{Kinetic\, energy}}}}{{{\rm{Retardins}}\;{\rm{\,force}}}} = \frac{{\frac{1}{2}m{u^2}}}{F}$
If retarding force $(F)$ and velocity $(v)$ are equal then stopping distance $(m)$ (mass of vehicle)
As ${m_{{\rm{car}}}} < {m_{{\rm{truck}}}}$ therefore car will cover less distance before coming to rest.

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Solution

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