A truck and a car are moving with equal velocity. On applying the brakes both will stop after certain distance, then
Truck will cover less distance before rest
Car will cover less distance before rest
Both will cover equal distance
None
The velocity $v$ of a body moving along a straight line varies with time $t$ as $v=2 t^2 e^{-t}$, where $v$ is in $m / s$ and $t$ is in second. The acceleration of body is zero at $t=$
A body starts from the origin and moves along the $X-$axis such that the velocity at any instant is given by $(4{t^3} - 2t)$, where $t$ is in sec and velocity in$m/s$. What is the acceleration of the particle, when it is $2\, m$ from the origin..........$m/{s^2}$
A particle initially at rest starts moving from reference point. $\mathrm{x}=0$ along $\mathrm{x}$-axis, with velocity $v$ that varies as $v=4 \sqrt{\mathrm{x} m} / \mathrm{s}$. The acceleration of the particle is __________$ \mathrm{ms}^{-2}$.
If $v = x^2 -5x + 4$, find the acceleration of particle when velocity of the particle is zero
The velocity-displacement graph of a particle is shown in the figure.
The acceleration-displacement graph of the same particle is represented by :