A body of mass (5 pm 0.5) kg is moving with a velocity of (20 pm 0.4) m / s . Its kinetic energy wil

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1.Units, Dimensions and Measurement

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A body of mass $(5 \pm 0.5) kg$ is moving with a velocity of $(20 \pm 0.4) m / s$. Its kinetic energy will be

A

$(1000 \pm 140)\,J$

B

$(1000 \pm 0.14)\,J$

C

$(500 \pm 0.14)\,J$

D

$(500 \pm 140)\,J$

(JEE MAIN-2023)

Solution

$k =\frac{1}{2} mv ^2$

$k =\frac{1}{2} \times 5 \times 400=5 \times 200=1000\,J$

$\frac{\Delta k }{2 k }=\frac{\Delta m }{ m }+\frac{2 \Delta v }{ v }=\frac{0.5}{5}+\frac{2 \times 0.4}{20}$

$\Delta k =1000\left(\frac{1}{10}+\frac{4}{100}\right)=1000\left(\frac{10+4}{100}\right)=140\,J$

Standard 11

Physics

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