A body of mass 5 kg is moving with a momentum of 10 kg m / s . A force of 0.2 N acts on it in direct

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5.Work, Energy, Power and Collision

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A body of mass $5\; kg$ is moving with a momentum of $10\; kg m / s$. A force of $0.2\; N$ acts on it in the direction of motion of the body for $10\; sec$. Find the increase in its kinetic energy.

A

$2.8 $

B

$3.2$

C

$3.8$

D

$4.4 $

Solution

$ {P_2} – {P_1} = F \times t$

==> ${P_2} = {P_1} + F \times t = 10 + 0.2 \times 10 = 12kg{\rm{ – }}m/s$

$E = \frac{1}{{2m}}[P_2^2 – P_1^2] = \frac{1}{{2m}}[{(12)^2} – {(10)^2}]$

$E= \frac{1}{{2 \times 5}}[144 – 100] = \frac{{44}}{{10}} = 4.4\;J$

Standard 11

Physics

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(JEE MAIN-2023)