A body of mass 5; kg is moving with a momentu | vedclass

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Question

$ {P_2} - {P_1} = F 	imes t$

==> ${P_2} = {P_1} + F 	imes t = 10 + 0.2 	imes 10 = 12kg{m{ - }}m/s$

$E = \frac{1}{{2m}}[P_2^2 - P_1^2] =

Vedclass · Accepted Answer

$4.4 $

Vedclass · Answer

$ {P_2} - {P_1} = F 	imes t$

==> ${P_2} = {P_1} + F 	imes t = 10 + 0.2 	imes 10 = 12kg{m{ - }}m/s$

$E = \frac{1}{{2m}}[P_2^2 - P_1^2] = \frac{1}{{2m}}[{(12)^2} - {(10)^2}]$

$E= \frac{1}{{2 	imes 5}}[144 - 100] = \frac{{44}}{{10}} = 4.4\;J$

A body of mass $5\; kg$ is moving with a momentum of $10\; kg m / s$. A force of $0.2\; N$ acts on it in the direction of motion of the body for $10\; sec$. Find the increase in its kinetic energy.

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