A body of mass $5\; kg$ is moving with a momentum of $10\; kg m / s$. A force of $0.2\; N$ acts on it in the direction of motion of the body for $10\; sec$. Find the increase in its kinetic energy.

A block moving horizontally on a smooth surface with a speed of $40\, {m} / {s}$ splits into two parts with masses in the ratio of $1: 2$. If the smaller part moves at $60\, {m} / {s}$ in the same direction, then the fractional change in kinetic energy is :-

Two solids $A$ and $B$ of mass $1\, kg$ and $2\, kg$ respectively are moving with equal linear momentum. The ratio of their kinetic energies $(K.E.)_{ A }:( K.E. )_{ B }$ will be $\frac{ A }{1},$ so the value of $A$ will be ..... .

If the kinetic energy of a body is directly proportional to time $t,$ the magnitude of force acting on the body is

$(i)$ directly proportional to $\sqrt t$
$(ii)$  inversely proportional to  $\sqrt t$
$(iii)$ directly proportional to the speed of the body
$(iv)$ inversely proportional to the speed of body

Is kinetic energy a scalar quantity or vector quantity ?

A $4 \,kg$ mass and a $1\, kg$ mass are moving with equal kinetic energies. The ratio of the magnitudes of their linear momenta is