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10-2.Transmission of Heat
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A body takes $5$ minutes for cooling from ${50^o}C$ to ${40^o}C.$ Its temperature comes down to ${33.33^o}C$ in next $5$ minutes. Temperature of surroundings is ....... $^oC$
A
$15$
B
$20$
C
$25$
D
$10$
Solution
(b) In first case $\frac{{50 – 40}}{5} = K\left[ {\frac{{50 + 40}}{2} – {\theta _0}} \right]$….$(i)$
In second case $\frac{{40 – 33.33}}{5} = K\left[ {\frac{{40 + 33.33}}{2} – \theta } \right]$….$(ii)$
By solving ${\theta _0} = {20^o}C$.
Standard 11
Physics
