આપેલ અંતર $ s = (13.8 \pm 0.2) m$  અને સમય $ t = (4.0 \pm 0.3) s$

વેગ $ \,V  =  \frac{s}{t}\,\, = \,\,\frac{{13.8}}{{4.0}}\,\, = \,\,3.45\,\,m{s^{ – 1}}\,\, = \,\,3.5\,\,m{s^{ – 1}}$

$\frac{{\Delta v}}{v}\,\, = \,\, \pm \,\,\left( {\frac{{\Delta s}}{s}\,\, + \,\,\frac{{\Delta t}}{t}} \right)\,\, = \,\, \pm \,\,\left( {\frac{{0.2}}{{13.8}}\,\, + \;\,\frac{{0.3}}{{4.0}}} \right)$

$ = \,\, \pm \,\,\left( {\frac{{0.8\,\, + \;\,4.14}}{{13.8\,\, \times \,\,4.0}}} \right)\,\, = \,\, \pm \,\,\frac{{4.49}}{{13.8\,\, \times \,\,4.0}}\,\, = \,\, \pm \,\,0.0895$

$\Delta \,v  =   \pm 0.0895\,\, \times \,\,v\,\, = \,\, \pm \,\,0.0895\,\, \times \,\,3.45\,\, = \,\, \pm 0.3087\,\, = \,\, \pm \,\,0.31$

$\therefore \,\,v  =  \left( {3.5\,\, \pm \,\,0.31} \right)\,m{s^{ – 1}}\,$

વેગમાં પ્રતિશત ત્રુટિ $ = \,\,\frac{{\Delta v}}{v}\,\, \times \,\,100\,\, = \,\, \pm \,\,0.0895\,\, \times \,\,100\,\, = \,\, \pm \,\,8.95\,\% \,\, = \,\, \pm \,\,9\% $