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5.Work, Energy, Power and Collision
medium
A bomb is kept stationary at a point. It suddenly explodes into two fragments of masses $1\, g$ and $3\;g$. The total K.E. of the fragments is $6.4 \times {10^4}J$. What is the K.E. of the smaller fragment
A
$2.5 \times {10^4}J$
B
$3.5 \times {10^4}J$
C
$4.8 \times {10^4}J$
D
$5.2 \times {10^4}J$
Solution
(c)As the momentum of both fragments are equal therefore
$\frac{{{E_1}}}{{{E_2}}} = \frac{{{m_2}}}{{{m_1}}} = \frac{3}{1}$
i.e. ${E_1} = 3{E_2}$…(i)
According to problem ${E_1} + {E_2} = 6.4 \times {10^4}J$ …(ii)
By solving equation (i) and (ii) we get
${E_1} = 4.8 \times {10^4}J$ and ${E_2} = 1.6 \times {10^4}J$
Standard 11
Physics
