3-2.Motion in Plane
easy

A bullet is fired from a gun at the speed of $280\,ms ^{-1}$ in the direction $30^{\circ}$ above the horizontal. The maximum height attained by the bullet is $........\,m$ $\left(g=9.8\,ms ^{-2}, \sin 30^{\circ}=0.5\right):-$

A

$3000$

B

$2800$

C

$2000$

D

$1000$

(NEET-2023)

Solution

$H _{\max }=\frac{ u ^2 \sin ^2 \theta}{2 g }$

$=\frac{(280)^2\left(\sin 30^{\circ}\right)^2}{2(9.8)}$

$=1000\,m$

Standard 11
Physics

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