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3-2.Motion in Plane
easy
A bullet is fired from a gun at the speed of $280\,ms ^{-1}$ in the direction $30^{\circ}$ above the horizontal. The maximum height attained by the bullet is $........\,m$ $\left(g=9.8\,ms ^{-2}, \sin 30^{\circ}=0.5\right):-$
A
$3000$
B
$2800$
C
$2000$
D
$1000$
(NEET-2023)
Solution
$H _{\max }=\frac{ u ^2 \sin ^2 \theta}{2 g }$
$=\frac{(280)^2\left(\sin 30^{\circ}\right)^2}{2(9.8)}$
$=1000\,m$
Standard 11
Physics