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Question

Assume acceleration of the car is a.

$PQ = s$

Using, $v^{2}=u^{2}+2$ as.

$\Rightarrow 40^{2}=30^{2}+2 a s$

$\Rightarrow 2$ as $=700\Righta

Vedclass · Accepted Answer

$25 \sqrt{2} \;km / h$

Vedclass · Answer

Assume acceleration of the car is a.

$PQ = s$

Using, $v^{2}=u^{2}+2$ as.

$\Rightarrow 40^{2}=30^{2}+2 a s$

$\Rightarrow 2$ as $=700\Rightarrow$ as $=350$

Now, assume velocity of car at a midpoint of $PQ$ is $V$. $V ^{2}= vp ^{2}+2 a \left(\frac{ s }{2}ight)$

$\Rightarrow V^{2}=900+350=1250$

$\Rightarrow V =35.35\;{ m }/{ s }$

OR

$V_{	ext {mid }}=\sqrt{\frac{V_{p}^{2}+V_{Q}^{2}}{2}}$

$V_{m i d}=\sqrt{\frac{30^{2}+40^{2}}{2}}$

$V_{mid} =\sqrt{\frac{900+1600}{{2}}}$

$V_{{mid}}=\sqrt{\frac{2500}{2}}$

$V_{{mid }} =25 \sqrt{2} m / s$

A car is moving along a straight road with a uniform acceleration. It passes through two points $P$ and $Q$ separated by a distance with velocity $30\; km / h$ and $40\; km / h$ respectively. The velocity of the car midway between $P$ and $Q$

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