A car is moving on a circular path of radius 500 m with speed 30 m/s and speed is increasing at rate

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3-2.Motion in Plane

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A car is moving on a circular path of radius $500\ m$ with speed $30\ m/s$ and speed is increasing at rate $2\ m/s^2$ net acceleration will be ......... $m/s^2$

A$2$

B$2.5$

C$2.7$

D$4$

Solution

$\begin{aligned} \mathrm{a}_{\mathrm{t}} &=2 \mathrm{m} / \mathrm{s}^{2} \\ \mathrm{a}_{\mathrm{c}} &=\frac{\mathrm{v}^{2}}{\mathrm{r}}=\frac{30^{2}}{500}=\frac{9}{5} \mathrm{m} / \mathrm{s}^{2} \\ \mathrm{a}_{\mathrm{net}} &=\sqrt{\mathrm{a}_{\mathrm{t}}^2+\mathrm{a}_{\mathrm{c}}^2} \\ &=\sqrt{2^{2}+(9 / 5)^{2}} \\ &=2.7 \mathrm{m} / \mathrm{s}^{2} \end{aligned}$

Standard 11

Physics

For a particle in a uniformly accelerated circular motion

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(AIIMS-2011)

$A$ disc is rotating with constant angular velocity about an axis passing through centre $C$ and perpendicular to the plane of disc. An insect is moving over the disc along radial direction with constant velocity with respect to the disc. Acceleration of the insect at the instant when its distance from centre is $r$, will be :-

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The velocity and acceleration vectors of a particle undergoing circular motion are $\overrightarrow{ v }=2 \hat{ i } m / s$ and $\overrightarrow{ a }=2 \hat{ i }+4 \hat{ j } m / s ^2$ respectively at an instant of time. The radius of the circle is $……..\,m$

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A particle moves in a circular path of radius $R$ with an angular velocity $\omega = a -bt$ where $a$ and $b$ are positive constants and $t$ is time. The magnitude of the acceleration of the particle after time $\frac {2a}{b}$ is

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An object is moving on a circular track of radius $450\, m$. At some instant, the object is moving at $30\, m/s$ and gaining speed at a uniform rate of $2 m/s^2$. Its acceleration at this instant is nearly ………. $m/s^2$

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A car is moving on a circular path of radius $500\ m$ with speed $30\ m/s$ and speed is increasing at rate $2\ m/s^2$ net acceleration will be ......... $m/s^2$

Solution

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