For a particle in a uniformly accelerated circular motion

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3-2.Motion in Plane

medium

For a particle in a uniformly accelerated circular motion

Avelocity is radial and acceleration has both radial and transverse components

Bvelocity is transverse and acceleration has both radial and transverse components

Cvelocity is radial and acceleration is transverse only

Dvelocity is transverse and acceleration is radial only

(AIIMS-2011)

Solution

For a uniformly accelerated motion there are two acceleration, one along the radius called radial acceleration and another along tangent called tangential acceleration. Velocity is directed along the tangent

Standard 11

Physics

The velocity and acceleration vectors of a particle undergoing circular motion are $\overrightarrow{ v }=2 \hat{ i } m / s$ and $\overrightarrow{ a }=2 \hat{ i }+4 \hat{ j } m / s ^2$ respectively at an instant of time. The radius of the circle is $……..\,m$

medium

A car is moving at a speed of $40\,m/s$ on a circular track of radius $400\,m.$ This speed is increasing at the rate of $3\,m/s^2.$ The acceleration of car is …….. $m/s^2$

medium

A car is moving on a circular path of radius $600\,m$ such that the magnitudes of the tangential acceleration and centripetal acceleration are equal. The time taken by the car to complete first quarter of revolution, if it is moving with an initial speed of $54\,km / hr$ is $t \left(1- e ^{-\pi / 2}\right)\,s$. The value of $t$ is $………….$.

hard

(JEE MAIN-2023)

A particle moves along an arc of a circle of radius $R$ . Its velocity depends on the distance covered as $v = a\sqrt s$ , where $a$ is a constant then the angle $\alpha $ between the vector of the total acceleration and the vector of velocity as a function of $s$ will be

hard

$A$ particle is moving along a circular path of radius $R$ in such a way that at any instant magnitude of radial acceleration & tangential acceleration are equal. If at $t = 0$ velocity of particle is $V_0$, the time period of first revolution of the particle is

normal

For a particle in a uniformly accelerated circular motion

Solution

Similar Questions

The velocity and acceleration vectors of a particle undergoing circular motion are $\overrightarrow{ v }=2 \hat{ i } m / s$ and $\overrightarrow{ a }=2 \hat{ i }+4 \hat{ j } m / s ^2$ respectively at an instant of time. The radius of the circle is $……..\,m$

A car is moving at a speed of $40\,m/s$ on a circular track of radius $400\,m.$ This speed is increasing at the rate of $3\,m/s^2.$ The acceleration of car is …….. $m/s^2$

A particle moves along an arc of a circle of radius $R$ . Its velocity depends on the distance covered as $v = a\sqrt s$ , where $a$ is a constant then the angle $\alpha $ between the vector of the total acceleration and the vector of velocity as a function of $s$ will be

$A$ particle is moving along a circular path of radius $R$ in such a way that at any instant magnitude of radial acceleration & tangential acceleration are equal. If at $t = 0$ velocity of particle is $V_0$, the time period of first revolution of the particle is

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