A car is moving with velocity V . If stop after applying break at a distance of 20 m . If velocity o

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2.Motion in Straight Line

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A car is moving with velocity $V$. If stop after applying break at a distance of $20\; m$. If velocity of car is doubled, then how much distance it will cover (travel) after applying break

A$160$

B$320$

C$80$

D$40$

Solution

$v^2=u^2-2 a s$
$s=\frac{u^2}{2 a} \Rightarrow s \propto u^2$
$\Rightarrow \frac{20}{s^{\prime}}=\frac{u^2}{4 u^2}$
$s^{\prime}=80$ meter

Standard 11

Physics

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