A car is moving with velocity $V$. If stop after applying break at a distance of $20\; m$. If velocity of car is doubled, then how much distance it will cover (travel) after applying break
$160$
$320$
$80$
$40$
The velocity-time and acceleration-time graphs of a particle are given as Its position-time graph may be gvien as
If the velocity $v$ of a particle moving along a straight line decreases linearly with its displacement $s$ from $20\,ms ^{-1}$ to a value approaching zero at $s=30\,m$, then acceleration of the particle at $s=15\,m$ is $........$
The distance travelled by a particle is related to time $t$ as $x =4 t ^2$. The velocity of the particle at $t =$ $5 s$ is $.........ms^{-1}$
The displacement is given by $x = 2{t^2} + t + 5$, the acceleration at $t = 2\;s$ is.........$m/{s^2}$
The displacement $(x)$ of a particle depends on time $t$ as $x=\alpha t^2-\beta t^3$. Choose the incorrect statements from the following.