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6.Permutation and Combination
medium
A car will hold $2$ in the front seat and $1$ in the rear seat. If among $6$ persons $2$ can drive, then the number of ways in which the car can be filled is
A
$10$
B
$20$
C
$30$
D
None of these
Solution
(b) Since $2$ persons can drive the car, therefore we have to select $1$ from these two. This can be done in $^2{C_1}$ ways. Now from the remaining $5$ persons we have to select $2$ which can be done in $^5{C_2}$ ways.
Therefore the required number of ways in which the car can be filled is $^5{C_2}{ \times ^2}{C_1} = 20$.
Standard 11
Mathematics