Gujarati
6.Permutation and Combination
easy

The number of ways in which we can select three numbers from $1$ to $30$ so as to exclude every selection of all even numbers is

A

$4060$

B

$3605$

C

$455$

D

None of these

Solution

(b) Required number of ways ${ = ^{30}}{C_3}{ – ^{15}}{C_3} = 3605$.

Standard 11
Mathematics

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