- Home
- Standard 11
- Mathematics
6.Permutation and Combination
easy
The number of ways in which we can select three numbers from $1$ to $30$ so as to exclude every selection of all even numbers is
A
$4060$
B
$3605$
C
$455$
D
None of these
Solution
(b) Required number of ways ${ = ^{30}}{C_3}{ – ^{15}}{C_3} = 3605$.
Standard 11
Mathematics
Similar Questions
medium