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6.Permutation and Combination
hard
If all the six digit numbers $x_1 x_2 x_3 x_4 x_5 x_6$ with $0 < x_1 < x_2 < x_3 < x_4 < x_5 < x_6$ are arranged in the increasing order, then the sum of the digits in the $72^{\text {th }}$ number is $............$.
A
$16$
B
$8$
C
$32$
D
$4$
(JEE MAIN-2023)
Solution
$245678 \rightarrow 72^{\text {th }} \text { word }$
$2+4+5+6+7+8=32$
Standard 11
Mathematics
