A card is selected from a pack of $52$ cards. Calculate the probability that the card is an ace
A card is selected from a pack of $52$ cards. Calculate the probability that the card is an ace
Let $E$ be the event in which the card drawn is an ace.
since there are $4$ ace in a pack of $52$ cards, $n(E)=4$
$\therefore P(E)=\frac{\text { Number of outcomes favourable to } E}{\text { Total mumber of possible outcomes }}=\frac{n(E)}{n(S)}=\frac{4}{52}=\frac{1}{13}$
Similar Questions
If the lengths of the sides of a triangle are decided by the three throws of a single fair die, then the probability that the triangle is of maximum area given that it is an isosceles triangle, is
If the lengths of the sides of a triangle are decided by the three throws of a single fair die, then the probability that the triangle is of maximum area given that it is an isosceles triangle, is
- [JEE MAIN 2015]
Three coins are tossed once. Find the probability of getting no tails.
Three coins are tossed once. Find the probability of getting no tails.
$A$ and $B$ toss a coin alternatively, the first to show a head being the winner. If $A$ starts the game, the chance of his winning is
$A$ and $B$ toss a coin alternatively, the first to show a head being the winner. If $A$ starts the game, the chance of his winning is
If $A$ and $B$ are two independent events such that $P\,(A \cap B') = \frac{3}{{25}}$ and $P\,(A' \cap B) = \frac{8}{{25}},$ then $P(A) = $
If $A$ and $B$ are two independent events such that $P\,(A \cap B') = \frac{3}{{25}}$ and $P\,(A' \cap B) = \frac{8}{{25}},$ then $P(A) = $
- [IIT 2002]
Let $A$ be a set of all $4 -$digit natural numbers whose exactly one digit is $7 .$ Then the probability that a randomly chosen element of $A$ leaves remainder $2$ when divided by $5$ is ..... .
Let $A$ be a set of all $4 -$digit natural numbers whose exactly one digit is $7 .$ Then the probability that a randomly chosen element of $A$ leaves remainder $2$ when divided by $5$ is ..... .
- [JEE MAIN 2021]