Three coins are tossed once. Let $A$ denote the event ' three heads show ', $B$ denote the event ' two heads and one tail show ' , $C$ denote the event ' three tails show and $D$ denote the event 'a head shows on the first coin '. Which events are Compound ?
When three coins are tossed, the sample space is given by
$S =\{ HHH ,\, HHT , \,HTH ,\, HTT , \,THH ,\, THT , \,TTH , \,TTT \}$
Accordingly,
$A=\{H H H\}$
$B =\{ HHT ,\, HTH ,\, THH \}$
$C =\{ TTT \}$
$D =\{ HHH , \,HHT , \,HTH , \,HTT \}$
We now observe that
$A \cap B$ $=\phi, A \cap C$ $=\phi, A \cap D$ $=\{H H H\} \neq \phi$
$B \cap C=\phi, B \cap D$ $=\{H H T,\, H T H\} \neq \phi$
$C \cap D=\phi$
If an event has more than one sample point of a sample space, it is called a compound event. Thus, $B$ and $D$ are compound events.
Two dice are thrown. The events $A, B$ and $C$ are as follows:
$A:$ getting an even number on the first die.
$B:$ getting an odd number on the first die.
$C:$ getting the sum of the numbers on the dice $\leq 5$
Describe the events $A^{\prime }.$
Two dice are thrown together. If the numbers appearing on the two dice are different, then what is the probability that the sum is $6$
The probability of drawing a white ball from a bag containing $3$ black balls and $4$ white balls, is
Consider the experiment of rolling a die. Let $A$ be the event 'getting a prime number ', $B$ be the event 'getting an odd number '. Write the sets representing the events $A$ or $B$.
Let $E$ and $F$ be two independent events. The probability that both $E$ and $F$ happen is $\frac{1}{12}$ and the probability that neither $E$ nor $F$ happens is $\frac{1}{2}$ , then a value of $\frac{{P(E)}}{{P\left( F \right)}}$ is