A charged particle of charge $\mathrm{e}$ and mass $\mathrm{m}$ is moving in an electric field ${{\rm{\vec E}}}$ and magnetic field ${{\rm{\vec B}}}$ Construct dimensionless quantities and quantities of dimension [T]-1
When electron enter in perpendicular magnetic field than magnetic force balance with centripetal force,
$\frac{m v^{2}}{\mathrm{R}}=q v \mathrm{~B}$
$\therefore\frac{q \mathrm{~B}}{m}=\frac{v}{\mathrm{R}}=\omega$
$\therefore\omega=\frac{v}{\mathrm{R}}=\frac{\mathrm{M}^{0} \mathrm{~L}^{1} \mathrm{~T}^{-1}}{\mathrm{~L}^{1}}=\mathrm{T}^{-1}$
Thus, angular frequency having dimension equal to $\mathrm{T}^{-1}$.
Maximum kinetic energy of the positive ion in the cyclotron is
A positively charged $(+ q)$ particle of mass $m$ has kinetic energy $K$ enters vertically downward in a horizontal field of magnetic induction $\overrightarrow B $ . The acceleration of the particle is :-
A charge particle of $2\,\mu\,C$ accelerated by a potential difference of $100\,V$ enters a region of uniform magnetic field of magnitude $4\,m\,T$ at right angle to the direction of field. The charge particle completes semicircle of radius $3\,cm$ inside magnetic field. The mass of the charge particle is $........\times 10^{-18}\,kg$.
A proton with a kinetic energy of $2.0\,eV$ moves into a region of uniform magnetic field of magnitude $\frac{\pi}{2} \times 10^{-3}\,T$. The angle between the direction of magnetic field and velocity of proton is $60^{\circ}$. The pitch of the helical path taken by the proton is $..........cm$ (Take, mass of proton $=1.6 \times 10^{-27}\,kg$ and Charge on proton $=1.6 \times 10^{-19}\,kg)$
A proton (mass $ = 1.67 \times {10^{ - 27}}\,kg$ and charge $ = 1.6 \times {10^{ - 19}}\,C)$ enters perpendicular to a magnetic field of intensity $2$ $weber/{m^2}$ with a velocity $3.4 \times {10^7}\,m/\sec $. The acceleration of the proton should be